Base | Representation |
---|---|
bin | 1100001000000110000101… |
… | …0100010011101001111011 |
3 | 1202012122100102011022211121 |
4 | 3002001201110103221323 |
5 | 3221422404031400443 |
6 | 44205105341010111 |
7 | 2544202255151263 |
oct | 302014124235173 |
9 | 52178312138747 |
10 | 13333211200123 |
11 | 4280646143221 |
12 | 15b4095553937 |
13 | 75941623c819 |
14 | 34148bc747a3 |
15 | 181c628314ed |
hex | c2061513a7b |
13333211200123 has 4 divisors (see below), whose sum is σ = 13422695839200. Its totient is φ = 13243726561048.
The previous prime is 13333211200117. The next prime is 13333211200163. The reversal of 13333211200123 is 32100211233331.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13333211200123 - 25 = 13333211200091 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13333211200163) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 44742319315 + ... + 44742319612.
It is an arithmetic number, because the mean of its divisors is an integer number (3355673959800).
Almost surely, 213333211200123 is an apocalyptic number.
13333211200123 is a deficient number, since it is larger than the sum of its proper divisors (89484639077).
13333211200123 is an equidigital number, since it uses as much as digits as its factorization.
13333211200123 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 89484639076.
The product of its (nonzero) digits is 1944, while the sum is 25.
Adding to 13333211200123 its reverse (32100211233331), we get a palindrome (45433422433454).
The spelling of 13333211200123 in words is "thirteen trillion, three hundred thirty-three billion, two hundred eleven million, two hundred thousand, one hundred twenty-three".
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