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133332312121 = 467285508163
BaseRepresentation
bin111110000101100111…
…0011010000000111001
3110202011011021020111021
41330023032122000321
54141031032441441
6141130234102441
712430045645021
oct1741316320071
9422134236437
10133332312121
1151600683598
1221a1087aa21
13c75b38b358
14664bc96a81
15370569a3d1
hex1f0b39a039

133332312121 has 4 divisors (see below), whose sum is σ = 133617820752. Its totient is φ = 133046803492.

The previous prime is 133332312107. The next prime is 133332312131. The reversal of 133332312121 is 121213233331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 133332312121 - 219 = 133331787833 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (133332312131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 142753615 + ... + 142754548.

It is an arithmetic number, because the mean of its divisors is an integer number (33404455188).

Almost surely, 2133332312121 is an apocalyptic number.

It is an amenable number.

133332312121 is a deficient number, since it is larger than the sum of its proper divisors (285508631).

133332312121 is an equidigital number, since it uses as much as digits as its factorization.

133332312121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 285508630.

The product of its digits is 1944, while the sum is 25.

Adding to 133332312121 its reverse (121213233331), we get a palindrome (254545545452).

The spelling of 133332312121 in words is "one hundred thirty-three billion, three hundred thirty-two million, three hundred twelve thousand, one hundred twenty-one".

Divisors: 1 467 285508163 133332312121