Base | Representation |
---|---|
bin | 11110010100101101101000… |
… | …000110101001010101110011 |
3 | 122111012112210112211102211002 |
4 | 132110231220012221111303 |
5 | 114440022030134041010 |
6 | 1151350533214512215 |
7 | 40043200322404502 |
oct | 3624555006512563 |
9 | 574175715742732 |
10 | 133364776080755 |
11 | 3954875831543a |
12 | 12b5aba180566b |
13 | 5955323cbc14b |
14 | 24d0c65100839 |
15 | 10641cd1741a5 |
hex | 794b681a9573 |
133364776080755 has 32 divisors (see below), whose sum is σ = 165805989258240. Its totient is φ = 102857432388480.
The previous prime is 133364776080751. The next prime is 133364776080761. The reversal of 133364776080755 is 557080677463331.
It is not a de Polignac number, because 133364776080755 - 22 = 133364776080751 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 133364776080691 and 133364776080700.
It is not an unprimeable number, because it can be changed into a prime (133364776080751) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 2277102482 + ... + 2277161048.
It is an arithmetic number, because the mean of its divisors is an integer number (5181437164320).
Almost surely, 2133364776080755 is an apocalyptic number.
133364776080755 is a deficient number, since it is larger than the sum of its proper divisors (32441213177485).
133364776080755 is a wasteful number, since it uses less digits than its factorization.
133364776080755 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 82019.
The product of its (nonzero) digits is 266716800, while the sum is 65.
The spelling of 133364776080755 in words is "one hundred thirty-three trillion, three hundred sixty-four billion, seven hundred seventy-six million, eighty thousand, seven hundred fifty-five".
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