Base | Representation |
---|---|
bin | 11000110101110101… |
… | …11010010001110001 |
3 | 1021102110002001210011 |
4 | 30122322322101301 |
5 | 204303124140221 |
6 | 10043212334521 |
7 | 651330553303 |
oct | 143272722161 |
9 | 37373061704 |
10 | 13336552561 |
11 | 5724155372 |
12 | 2702474441 |
13 | 134702a127 |
14 | 907335973 |
15 | 530c811e1 |
hex | 31aeba471 |
13336552561 has 4 divisors (see below), whose sum is σ = 14038476400. Its totient is φ = 12634628724.
The previous prime is 13336552511. The next prime is 13336552577. The reversal of 13336552561 is 16525563331.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 16525563331 = 353 ⋅46814627.
It is a cyclic number.
It is not a de Polignac number, because 13336552561 - 27 = 13336552433 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13336552511) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 350961891 + ... + 350961928.
It is an arithmetic number, because the mean of its divisors is an integer number (3509619100).
Almost surely, 213336552561 is an apocalyptic number.
It is an amenable number.
13336552561 is a deficient number, since it is larger than the sum of its proper divisors (701923839).
13336552561 is an equidigital number, since it uses as much as digits as its factorization.
13336552561 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 701923838.
The product of its digits is 243000, while the sum is 40.
The spelling of 13336552561 in words is "thirteen billion, three hundred thirty-six million, five hundred fifty-two thousand, five hundred sixty-one".
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