Base | Representation |
---|---|
bin | 1100001000011111011111… |
… | …0101000101011000101010 |
3 | 1202020021221201110102211102 |
4 | 3002013313311011120222 |
5 | 3222030341010421442 |
6 | 44212154212201402 |
7 | 2544533261333222 |
oct | 302076765053052 |
9 | 52207851412742 |
10 | 13340031342122 |
11 | 4283525a11911 |
12 | 15b5479609262 |
13 | 759c621c13c4 |
14 | 341937973082 |
15 | 18201146e232 |
hex | c21f7d4562a |
13340031342122 has 8 divisors (see below), whose sum is σ = 20291878661472. Its totient is φ = 6576071788300.
The previous prime is 13340031342061. The next prime is 13340031342137. The reversal of 13340031342122 is 22124313004331.
13340031342122 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a super-3 number, since 3×133400313421223 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 46971941204 + ... + 46971941487.
It is an arithmetic number, because the mean of its divisors is an integer number (2536484832684).
Almost surely, 213340031342122 is an apocalyptic number.
13340031342122 is a deficient number, since it is larger than the sum of its proper divisors (6951847319350).
13340031342122 is an equidigital number, since it uses as much as digits as its factorization.
13340031342122 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 93943882764.
The product of its (nonzero) digits is 10368, while the sum is 29.
Adding to 13340031342122 its reverse (22124313004331), we get a palindrome (35464344346453).
The spelling of 13340031342122 in words is "thirteen trillion, three hundred forty billion, thirty-one million, three hundred forty-two thousand, one hundred twenty-two".
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