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13340111400 = 23335271132083
BaseRepresentation
bin11000110110010000…
…11111001000101000
31021102200202212121000
430123020133020220
5204310032031100
610043420515000
7651403035030
oct143310371050
937380685530
1013340111400
115726166160
1227036aba60
1313479a4c55
149079c08c0
15531235900
hex31b21f228

13340111400 has 384 divisors, whose sum is σ = 57289190400. Its totient is φ = 2771884800.

The previous prime is 13340111359. The next prime is 13340111417. The reversal of 13340111400 is 411104331.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is an unprimeable number.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 399759 + ... + 431841.

It is an arithmetic number, because the mean of its divisors is an integer number (149190600).

Almost surely, 213340111400 is an apocalyptic number.

13340111400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13340111400, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (28644595200).

13340111400 is an abundant number, since it is smaller than the sum of its proper divisors (43949079000).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13340111400 is a wasteful number, since it uses less digits than its factorization.

13340111400 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 32126 (or 32111 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 18.

Adding to 13340111400 its reverse (411104331), we get a palindrome (13751215731).

The spelling of 13340111400 in words is "thirteen billion, three hundred forty million, one hundred eleven thousand, four hundred".