133401451335401 has 4 divisors (see below), whose sum is σ = 133406369025792. Its totient is φ = 133396533645012.

The previous prime is 133401451335391. The next prime is 133401451335403. The reversal of 133401451335401 is 104533154104331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-133401451335401 is a prime.

It is a super-2 number, since 2×133401451335401² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (133401451335403) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2458804505 + ... + 2458858758.

It is an arithmetic number, because the mean of its divisors is an integer number (33351592256448).

Almost surely, 2^{133401451335401} is an apocalyptic number.

It is an amenable number.

133401451335401 is a deficient number, since it is larger than the sum of its proper divisors (4917690391).

133401451335401 is an equidigital number, since it uses as much as digits as its factorization.

133401451335401 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4917690390.

The product of its (nonzero) digits is 129600, while the sum is 38.

The spelling of 133401451335401 in words is "one hundred thirty-three trillion, four hundred one billion, four hundred fifty-one million, three hundred thirty-five thousand, four hundred one".