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13340152555 = 510692495819
BaseRepresentation
bin11000110110010001…
…01001001011101011
31021102200211222001021
430123020221023223
5204310034340210
610043421433311
7651403266022
oct143310511353
937380758037
1013340152555
115726194074
12270370b837
1313479ba8c2
149079d18b9
15531242bda
hex31b2292eb

13340152555 has 8 divisors (see below), whose sum is σ = 16023164400. Its totient is φ = 10662134496.

The previous prime is 13340152549. The next prime is 13340152577. The reversal of 13340152555 is 55525104331.

13340152555 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13340152555 - 29 = 13340152043 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 13340152555.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1242565 + ... + 1253254.

It is an arithmetic number, because the mean of its divisors is an integer number (2002895550).

Almost surely, 213340152555 is an apocalyptic number.

13340152555 is a deficient number, since it is larger than the sum of its proper divisors (2683011845).

13340152555 is a wasteful number, since it uses less digits than its factorization.

13340152555 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2496893.

The product of its (nonzero) digits is 45000, while the sum is 34.

Adding to 13340152555 its reverse (55525104331), we get a palindrome (68865256886).

The spelling of 13340152555 in words is "thirteen billion, three hundred forty million, one hundred fifty-two thousand, five hundred fifty-five".

Divisors: 1 5 1069 5345 2495819 12479095 2668030511 13340152555