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13340342401 = 23580014887
BaseRepresentation
bin11000110110010010…
…10111100010000001
31021102201012121110121
430123021113202001
5204310111424101
610043425500241
7651405016351
oct143311274201
937381177417
1013340342401
115726303771
1227037a1681
131347a56139
14907a40b61
1553127e0a1
hex31b257881

13340342401 has 4 divisors (see below), whose sum is σ = 13920357312. Its totient is φ = 12760327492.

The previous prime is 13340342381. The next prime is 13340342413. The reversal of 13340342401 is 10424304331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 10424304331 = 71489186333.

It is a cyclic number.

It is not a de Polignac number, because 13340342401 - 27 = 13340342273 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13340342801) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 290007421 + ... + 290007466.

It is an arithmetic number, because the mean of its divisors is an integer number (3480089328).

Almost surely, 213340342401 is an apocalyptic number.

It is an amenable number.

13340342401 is a deficient number, since it is larger than the sum of its proper divisors (580014911).

13340342401 is an equidigital number, since it uses as much as digits as its factorization.

13340342401 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 580014910.

The product of its (nonzero) digits is 3456, while the sum is 25.

Adding to 13340342401 its reverse (10424304331), we get a palindrome (23764646732).

The spelling of 13340342401 in words is "thirteen billion, three hundred forty million, three hundred forty-two thousand, four hundred one".

Divisors: 1 23 580014887 13340342401