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133404034 = 266702017
BaseRepresentation
bin1111111001110…
…01010110000010
3100022000121221011
413330321112002
5233122412114
621123151134
73206626021
oct774712602
9308017834
10133404034
1169337475
12388154aa
132183acca
1413a088b8
15baa21c4
hex7f39582

133404034 has 4 divisors (see below), whose sum is σ = 200106054. Its totient is φ = 66702016.

The previous prime is 133404023. The next prime is 133404053. The reversal of 133404034 is 430404331.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 430404331 = 761486333.

It can be written as a sum of positive squares in only one way, i.e., 103734225 + 29669809 = 10185^2 + 5447^2 .

It is a super-3 number, since 3×1334040343 (a number of 25 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 133403996 and 133404014.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 33351007 + ... + 33351010.

Almost surely, 2133404034 is an apocalyptic number.

133404034 is a deficient number, since it is larger than the sum of its proper divisors (66702020).

133404034 is an equidigital number, since it uses as much as digits as its factorization.

133404034 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 66702019.

The product of its (nonzero) digits is 1728, while the sum is 22.

The square root of 133404034 is about 11550.0664067355. The cubic root of 133404034 is about 510.9632366197.

Adding to 133404034 its reverse (430404331), we get a palindrome (563808365).

The spelling of 133404034 in words is "one hundred thirty-three million, four hundred four thousand, thirty-four".

Divisors: 1 2 66702017 133404034