13340406671 has 4 divisors (see below), whose sum is σ = 13352502432. Its totient is φ = 13328310912.

The previous prime is 13340406659. The next prime is 13340406683. The reversal of 13340406671 is 17660404331.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 17660404331 = 73 ⋅241923347.

It is an interprime number because it is at equal distance from previous prime (13340406659) and next prime (13340406683).

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13340406671 is a prime.

It is a super-2 number, since 2×13340406671² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13340406631) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6046226 + ... + 6048431.

It is an arithmetic number, because the mean of its divisors is an integer number (3338125608).

Almost surely, 2^13340406671 is an apocalyptic number.

13340406671 is a deficient number, since it is larger than the sum of its proper divisors (12095761).

13340406671 is a wasteful number, since it uses less digits than its factorization.

13340406671 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12095760.

The product of its (nonzero) digits is 36288, while the sum is 35.

The spelling of 13340406671 in words is "thirteen billion, three hundred forty million, four hundred six thousand, six hundred seventy-one".