Base | Representation |
---|---|
bin | 1100001000100000111100… |
… | …0001010001011110011101 |
3 | 1202020022221211120022012120 |
4 | 3002020033001101132131 |
5 | 3222032140111211331 |
6 | 44212300551253153 |
7 | 2544546024356520 |
oct | 302101701213635 |
9 | 52208854508176 |
10 | 13340420413341 |
11 | 42837055a287a |
12 | 15b556797a1b9 |
13 | 759cc49a7468 |
14 | 3419734d0bb7 |
15 | 1820356c4796 |
hex | c220f05179d |
13340420413341 has 16 divisors (see below), whose sum is σ = 20330419572864. Its totient is φ = 7622287418304.
The previous prime is 13340420413337. The next prime is 13340420413373. The reversal of 13340420413341 is 14331402404331.
It is not a de Polignac number, because 13340420413341 - 22 = 13340420413337 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13340420413301) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 33545986 + ... + 33941331.
It is an arithmetic number, because the mean of its divisors is an integer number (1270651223304).
Almost surely, 213340420413341 is an apocalyptic number.
It is an amenable number.
13340420413341 is a deficient number, since it is larger than the sum of its proper divisors (6989999159523).
13340420413341 is an equidigital number, since it uses as much as digits as its factorization.
13340420413341 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 67496740.
The product of its (nonzero) digits is 41472, while the sum is 33.
Adding to 13340420413341 its reverse (14331402404331), we get a palindrome (27671822817672).
The spelling of 13340420413341 in words is "thirteen trillion, three hundred forty billion, four hundred twenty million, four hundred thirteen thousand, three hundred forty-one".
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