1334043110131 has 4 divisors (see below), whose sum is σ = 1340955250792. Its totient is φ = 1327130969472.

The previous prime is 1334043110093. The next prime is 1334043110161. The reversal of 1334043110131 is 1310113404331.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1334043110131 - 2²⁷ = 1333908892403 is a prime.

It is a super-2 number, since 2×1334043110131² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1334043110096 and 1334043110105.

It is not an unprimeable number, because it can be changed into a prime (1334043110161) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3456070041 + ... + 3456070426.

It is an arithmetic number, because the mean of its divisors is an integer number (335238812698).

Almost surely, 2^{1334043110131} is an apocalyptic number.

1334043110131 is a deficient number, since it is larger than the sum of its proper divisors (6912140661).

1334043110131 is an equidigital number, since it uses as much as digits as its factorization.

1334043110131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6912140660.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 1334043110131 its reverse (1310113404331), we get a palindrome (2644156514462).

The spelling of 1334043110131 in words is "one trillion, three hundred thirty-four billion, forty-three million, one hundred ten thousand, one hundred thirty-one".