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13340433 = 34794613
BaseRepresentation
bin110010111000…
…111100010001
3221002202122010
4302320330101
511403343213
61153533133
7221251251
oct62707421
927082563
1013340433
117591957
1245741a9
1329c1162
141ab3961
151287ac3
hexcb8f11

13340433 has 8 divisors (see below), whose sum is σ = 18165888. Its totient is φ = 8704304.

The previous prime is 13340423. The next prime is 13340443. The reversal of 13340433 is 33404331.

13340433 is nontrivially palindromic in base 11.

13340433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is an interprime number because it is at equal distance from previous prime (13340423) and next prime (13340443).

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13340433 - 214 = 13324049 is a prime.

It is not an unprimeable number, because it can be changed into a prime (13340423) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 47166 + ... + 47447.

It is an arithmetic number, because the mean of its divisors is an integer number (2270736).

Almost surely, 213340433 is an apocalyptic number.

It is an amenable number.

13340433 is a deficient number, since it is larger than the sum of its proper divisors (4825455).

13340433 is an equidigital number, since it uses as much as digits as its factorization.

13340433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 94663.

The product of its (nonzero) digits is 1296, while the sum is 21.

The square root of 13340433 is about 3652.4557492186. The cubic root of 13340433 is about 237.1683007593.

Adding to 13340433 its reverse (33404331), we get a palindrome (46744764).

The spelling of 13340433 in words is "thirteen million, three hundred forty thousand, four hundred thirty-three".

Divisors: 1 3 47 141 94613 283839 4446811 13340433