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13340433415 = 52668086683
BaseRepresentation
bin11000110110010011…
…01101110000000111
31021102201101020022111
430123021231300013
5204310122332130
610043431441451
7651405545611
oct143311556007
937381336274
1013340433415
115726366091
122703826287
131347a886aa
14907a65db1
1553129b02a
hex31b26dc07

13340433415 has 4 divisors (see below), whose sum is σ = 16008520104. Its totient is φ = 10672346728.

The previous prime is 13340433397. The next prime is 13340433437. The reversal of 13340433415 is 51433404331.

13340433415 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13340433415 is a prime.

It is a Duffinian number.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1334043337 + ... + 1334043346.

It is an arithmetic number, because the mean of its divisors is an integer number (4002130026).

Almost surely, 213340433415 is an apocalyptic number.

13340433415 is a deficient number, since it is larger than the sum of its proper divisors (2668086689).

13340433415 is an equidigital number, since it uses as much as digits as its factorization.

13340433415 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2668086688.

The product of its (nonzero) digits is 25920, while the sum is 31.

Adding to 13340433415 its reverse (51433404331), we get a palindrome (64773837746).

The spelling of 13340433415 in words is "thirteen billion, three hundred forty million, four hundred thirty-three thousand, four hundred fifteen".

Divisors: 1 5 2668086683 13340433415