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13341102353345 = 5131910802512027
BaseRepresentation
bin1100001000100011011110…
…1010101010101111000001
31202020101201100202110000202
43002020313222222233001
53222040034200301340
644212452351454545
72544601644642014
oct302106752525701
952211640673022
1013341102353345
114283a25527458
1215b5718227455
1375a0a3062460
143419d9cc737b
151820754cac15
hexc2237aaabc1

13341102353345 has 16 divisors (see below), whose sum is σ = 18148220207040. Its totient is φ = 9333370390464.

The previous prime is 13341102353303. The next prime is 13341102353357. The reversal of 13341102353345 is 54335320114331.

It is a cyclic number.

It is not a de Polignac number, because 13341102353345 - 212 = 13341102349249 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13341102353299 and 13341102353308.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 5401254779 + ... + 5401257248.

It is an arithmetic number, because the mean of its divisors is an integer number (1134263762940).

Almost surely, 213341102353345 is an apocalyptic number.

It is an amenable number.

13341102353345 is a deficient number, since it is larger than the sum of its proper divisors (4807117853695).

13341102353345 is a wasteful number, since it uses less digits than its factorization.

13341102353345 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10802512064.

The product of its (nonzero) digits is 194400, while the sum is 38.

Adding to 13341102353345 its reverse (54335320114331), we get a palindrome (67676422467676).

The spelling of 13341102353345 in words is "thirteen trillion, three hundred forty-one billion, one hundred two million, three hundred fifty-three thousand, three hundred forty-five".

Divisors: 1 5 13 19 65 95 247 1235 10802512027 54012560135 140432656351 205247728513 702163281755 1026238642565 2668220470669 13341102353345