13341112022403 has 64 divisors (see below), whose sum is σ = 22061027289600. Its totient is φ = 7900229998080.

The previous prime is 13341112022389. The next prime is 13341112022419. The reversal of 13341112022403 is 30422021114331.

13341112022403 is a `hidden beast` number, since 1 + 3 + 3 + 41 + 11 + 202 + 2 + 403 = 666.

It is not a de Polignac number, because 13341112022403 - 2¹⁸ = 13341111760259 is a prime.

It is a super-3 number, since 3×13341112022403³ (a number of 40 digits) contains 333 as substring.

It is a Harshad number since it is a multiple of its sum of digits (27).

It is not an unprimeable number, because it can be changed into a prime (13341112022453) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 555538 + ... + 5195271.

It is an arithmetic number, because the mean of its divisors is an integer number (344703551400).

Almost surely, 2^{13341112022403} is an apocalyptic number.

13341112022403 is a deficient number, since it is larger than the sum of its proper divisors (8719915267197).

13341112022403 is a wasteful number, since it uses less digits than its factorization.

13341112022403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5751009 (or 5751003 counting only the distinct ones).

The product of its (nonzero) digits is 3456, while the sum is 27.

Adding to 13341112022403 its reverse (30422021114331), we get a palindrome (43763133136734).

The spelling of 13341112022403 in words is "thirteen trillion, three hundred forty-one billion, one hundred twelve million, twenty-two thousand, four hundred three".