13341141320033 has 4 divisors (see below), whose sum is σ = 13624995390720. Its totient is φ = 13057287249348.

The previous prime is 13341141320029. The next prime is 13341141320041. The reversal of 13341141320033 is 33002314114331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13341141320033 - 2² = 13341141320029 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13341141319978 and 13341141320005.

It is not an unprimeable number, because it can be changed into a prime (13341141320083) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 141927035273 + ... + 141927035366.

It is an arithmetic number, because the mean of its divisors is an integer number (3406248847680).

Almost surely, 2^{13341141320033} is an apocalyptic number.

It is an amenable number.

13341141320033 is a deficient number, since it is larger than the sum of its proper divisors (283854070687).

13341141320033 is an equidigital number, since it uses as much as digits as its factorization.

13341141320033 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 283854070686.

The product of its (nonzero) digits is 7776, while the sum is 29.

Adding to 13341141320033 its reverse (33002314114331), we get a palindrome (46343455434364).

The spelling of 13341141320033 in words is "thirteen trillion, three hundred forty-one billion, one hundred forty-one million, three hundred twenty thousand, thirty-three".