Base | Representation |
---|---|
bin | 111110000111111110… |
… | …0001101111110111111 |
3 | 110202100200010212021111 |
4 | 1330033330031332333 |
5 | 4141211311232320 |
6 | 141142141542451 |
7 | 12432026306251 |
oct | 1741774157677 |
9 | 422320125244 |
10 | 133411430335 |
11 | 51641302247 |
12 | 21a33274a27 |
13 | c7718a0271 |
14 | 66585adcd1 |
15 | 370c5c7a5a |
hex | 1f0ff0dfbf |
133411430335 has 8 divisors (see below), whose sum is σ = 160522924320. Its totient is φ = 106443005664.
The previous prime is 133411430291. The next prime is 133411430353. The reversal of 133411430335 is 533034114331.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 133411430335 - 211 = 133411428287 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 133411430297 and 133411430306.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 35765275 + ... + 35769004.
It is an arithmetic number, because the mean of its divisors is an integer number (20065365540).
Almost surely, 2133411430335 is an apocalyptic number.
133411430335 is a deficient number, since it is larger than the sum of its proper divisors (27111493985).
133411430335 is an equidigital number, since it uses as much as digits as its factorization.
133411430335 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 71534657.
The product of its (nonzero) digits is 19440, while the sum is 31.
Adding to 133411430335 its reverse (533034114331), we get a palindrome (666445544666).
The spelling of 133411430335 in words is "one hundred thirty-three billion, four hundred eleven million, four hundred thirty thousand, three hundred thirty-five".
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