Base | Representation |
---|---|
bin | 11110010101011001101110… |
… | …001001110010111111000001 |
3 | 122111101002000011221000111102 |
4 | 132111121232021302333001 |
5 | 114441311011241211431 |
6 | 1151424403254424145 |
7 | 40046464521021440 |
oct | 3625315611627701 |
9 | 574332004830442 |
10 | 133412122210241 |
11 | 39566843a39276 |
12 | 12b681b5962055 |
13 | 595992aca6b94 |
14 | 24d32771a8d57 |
15 | 106554ea46dcb |
hex | 79566e272fc1 |
133412122210241 has 8 divisors (see below), whose sum is σ = 152843786538240. Its totient is φ = 114073655313888.
The previous prime is 133412122210193. The next prime is 133412122210249. The reversal of 133412122210241 is 142012221214331.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 133412122210241 - 222 = 133412118015937 is a prime.
It is not an unprimeable number, because it can be changed into a prime (133412122210249) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 23299354841 + ... + 23299360566.
It is an arithmetic number, because the mean of its divisors is an integer number (19105473317280).
Almost surely, 2133412122210241 is an apocalyptic number.
It is an amenable number.
133412122210241 is a deficient number, since it is larger than the sum of its proper divisors (19431664327999).
133412122210241 is an equidigital number, since it uses as much as digits as its factorization.
133412122210241 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 46598715823.
The product of its (nonzero) digits is 4608, while the sum is 29.
Adding to 133412122210241 its reverse (142012221214331), we get a palindrome (275424343424572).
The spelling of 133412122210241 in words is "one hundred thirty-three trillion, four hundred twelve billion, one hundred twenty-two million, two hundred ten thousand, two hundred forty-one".
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