Base | Representation |
---|---|
bin | 11110010101011001101110… |
… | …001001110010111110010001 |
3 | 122111101002000011221000102122 |
4 | 132111121232021302332101 |
5 | 114441311011241211233 |
6 | 1151424403254424025 |
7 | 40046464521021341 |
oct | 3625315611627621 |
9 | 574332004830378 |
10 | 133412122210193 |
11 | 39566843a39232 |
12 | 12b681b5962015 |
13 | 595992aca6b58 |
14 | 24d32771a8d21 |
15 | 106554ea46d98 |
hex | 79566e272f91 |
133412122210193 has 2 divisors, whose sum is σ = 133412122210194. Its totient is φ = 133412122210192.
The previous prime is 133412122210153. The next prime is 133412122210249. The reversal of 133412122210193 is 391012221214331.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 130595709911104 + 2816412299089 = 11427848^2 + 1678217^2 .
It is a cyclic number.
It is not a de Polignac number, because 133412122210193 - 220 = 133412121161617 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is not a weakly prime, because it can be changed into another prime (133412122210153) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66706061105096 + 66706061105097.
It is an arithmetic number, because the mean of its divisors is an integer number (66706061105097).
Almost surely, 2133412122210193 is an apocalyptic number.
It is an amenable number.
133412122210193 is a deficient number, since it is larger than the sum of its proper divisors (1).
133412122210193 is an equidigital number, since it uses as much as digits as its factorization.
133412122210193 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15552, while the sum is 35.
The spelling of 133412122210193 in words is "one hundred thirty-three trillion, four hundred twelve billion, one hundred twenty-two million, two hundred ten thousand, one hundred ninety-three".
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