Base | Representation |
---|---|
bin | 10011011010011111111… |
… | …000000000100001110111 |
3 | 11201112121021010211000211 |
4 | 103122133320000201313 |
5 | 133324240230340320 |
6 | 2500515351050251 |
7 | 165246534631603 |
oct | 23323770004167 |
9 | 4645537124024 |
10 | 1334122121335 |
11 | 47488617aa73 |
12 | 19668a970987 |
13 | 98a6549b593 |
14 | 48801256503 |
15 | 24a8489855a |
hex | 1369fe00877 |
1334122121335 has 16 divisors (see below), whose sum is σ = 1678133429280. Its totient is φ = 1017050549760.
The previous prime is 1334122121309. The next prime is 1334122121393. The reversal of 1334122121335 is 5331212214331.
It is not a de Polignac number, because 1334122121335 - 211 = 1334122119287 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1334122121297 and 1334122121306.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 75664590 + ... + 75682219.
It is an arithmetic number, because the mean of its divisors is an integer number (104883339330).
Almost surely, 21334122121335 is an apocalyptic number.
1334122121335 is a deficient number, since it is larger than the sum of its proper divisors (344011307945).
1334122121335 is a wasteful number, since it uses less digits than its factorization.
1334122121335 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 151346898.
The product of its digits is 12960, while the sum is 31.
Adding to 1334122121335 its reverse (5331212214331), we get a palindrome (6665334335666).
The spelling of 1334122121335 in words is "one trillion, three hundred thirty-four billion, one hundred twenty-two million, one hundred twenty-one thousand, three hundred thirty-five".
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