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1334122121335 = 54143151346809
BaseRepresentation
bin10011011010011111111…
…000000000100001110111
311201112121021010211000211
4103122133320000201313
5133324240230340320
62500515351050251
7165246534631603
oct23323770004167
94645537124024
101334122121335
1147488617aa73
1219668a970987
1398a6549b593
1448801256503
1524a8489855a
hex1369fe00877

1334122121335 has 16 divisors (see below), whose sum is σ = 1678133429280. Its totient is φ = 1017050549760.

The previous prime is 1334122121309. The next prime is 1334122121393. The reversal of 1334122121335 is 5331212214331.

It is not a de Polignac number, because 1334122121335 - 211 = 1334122119287 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1334122121297 and 1334122121306.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 75664590 + ... + 75682219.

It is an arithmetic number, because the mean of its divisors is an integer number (104883339330).

Almost surely, 21334122121335 is an apocalyptic number.

1334122121335 is a deficient number, since it is larger than the sum of its proper divisors (344011307945).

1334122121335 is a wasteful number, since it uses less digits than its factorization.

1334122121335 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 151346898.

The product of its digits is 12960, while the sum is 31.

Adding to 1334122121335 its reverse (5331212214331), we get a palindrome (6665334335666).

The spelling of 1334122121335 in words is "one trillion, three hundred thirty-four billion, one hundred twenty-two million, one hundred twenty-one thousand, three hundred thirty-five".

Divisors: 1 5 41 43 205 215 1763 8815 151346809 756734045 6205219169 6507912787 31026095845 32539563935 266824424267 1334122121335