Base | Representation |
---|---|
bin | 11110010101011010110001… |
… | …011000000001010101011001 |
3 | 122111101011220210002022100122 |
4 | 132111122301120001111121 |
5 | 114441320314000400010 |
6 | 1151425111223243025 |
7 | 40046534464130621 |
oct | 3625326130012531 |
9 | 574334823068318 |
10 | 133413250012505 |
11 | 39567272612861 |
12 | 12b6846b5a9475 |
13 | 5959a7a8403b8 |
14 | 24d3342ca3881 |
15 | 10655b8a70855 |
hex | 7956b1601559 |
133413250012505 has 4 divisors (see below), whose sum is σ = 160095900015012. Its totient is φ = 106730600010000.
The previous prime is 133413250012451. The next prime is 133413250012531. The reversal of 133413250012505 is 505210052314331.
It is a happy number.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 104918803168144 + 28494446844361 = 10242988^2 + 5338019^2 .
It is not a de Polignac number, because 133413250012505 - 28 = 133413250012249 is a prime.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13341325001246 + ... + 13341325001255.
It is an arithmetic number, because the mean of its divisors is an integer number (40023975003753).
Almost surely, 2133413250012505 is an apocalyptic number.
It is an amenable number.
133413250012505 is a deficient number, since it is larger than the sum of its proper divisors (26682650002507).
133413250012505 is an equidigital number, since it uses as much as digits as its factorization.
133413250012505 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 26682650002506.
The product of its (nonzero) digits is 54000, while the sum is 35.
The spelling of 133413250012505 in words is "one hundred thirty-three trillion, four hundred thirteen billion, two hundred fifty million, twelve thousand, five hundred five".
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