13341401242301 has 4 divisors (see below), whose sum is σ = 14554255900704. Its totient is φ = 12128546583900.

The previous prime is 13341401242291. The next prime is 13341401242373. The reversal of 13341401242301 is 10324210414331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13341401242301 - 2³⁰ = 13340327500477 is a prime.

It is a super-2 number, since 2×13341401242301² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13341401242201) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 606427329185 + ... + 606427329206.

It is an arithmetic number, because the mean of its divisors is an integer number (3638563975176).

Almost surely, 2^{13341401242301} is an apocalyptic number.

13341401242301 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

13341401242301 is a deficient number, since it is larger than the sum of its proper divisors (1212854658403).

13341401242301 is a wasteful number, since it uses less digits than its factorization.

13341401242301 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1212854658402.

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 13341401242301 its reverse (10324210414331), we get a palindrome (23665611656632).

The spelling of 13341401242301 in words is "thirteen trillion, three hundred forty-one billion, four hundred one million, two hundred forty-two thousand, three hundred one".