Base | Representation |
---|---|
bin | 1100001000100100100110… |
… | …1110000100001111001001 |
3 | 1202020102111110200101100021 |
4 | 3002021021232010033021 |
5 | 3222041144214442441 |
6 | 44212542411340441 |
7 | 2544612313250236 |
oct | 302111156041711 |
9 | 52212443611307 |
10 | 13341405234121 |
11 | 4284070499248 |
12 | 15b57a1751721 |
13 | 75a120a2b553 |
14 | 341a2820a78d |
15 | 182091da83d1 |
hex | c2249b843c9 |
13341405234121 has 8 divisors (see below), whose sum is σ = 13801571521920. Its totient is φ = 12881246801808.
The previous prime is 13341405234089. The next prime is 13341405234161. The reversal of 13341405234121 is 12143250414331.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 13341405234121 - 25 = 13341405234089 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13341405234161) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1601130 + ... + 5407996.
It is an arithmetic number, because the mean of its divisors is an integer number (1725196440240).
Almost surely, 213341405234121 is an apocalyptic number.
It is an amenable number.
13341405234121 is a deficient number, since it is larger than the sum of its proper divisors (460166287799).
13341405234121 is a wasteful number, since it uses less digits than its factorization.
13341405234121 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3927743.
The product of its (nonzero) digits is 34560, while the sum is 34.
Adding to 13341405234121 its reverse (12143250414331), we get a palindrome (25484655648452).
The spelling of 13341405234121 in words is "thirteen trillion, three hundred forty-one billion, four hundred five million, two hundred thirty-four thousand, one hundred twenty-one".
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