Base | Representation |
---|---|
bin | 11110010101011011110001… |
… | …111000101000001110000011 |
3 | 122111101021201012121022201120 |
4 | 132111123301320220032003 |
5 | 114441330023032132321 |
6 | 1151425410444403323 |
7 | 40046603345342322 |
oct | 3625336170501603 |
9 | 574337635538646 |
10 | 133414332302211 |
11 | 39567778531064 |
12 | 12b68711b46543 |
13 | 5959bc0b2cbcc |
14 | 24d34069120b9 |
15 | 106562daa8ec6 |
hex | 7956f1e28383 |
133414332302211 has 32 divisors (see below), whose sum is σ = 186790186598400. Its totient is φ = 84590467585440.
The previous prime is 133414332302183. The next prime is 133414332302221. The reversal of 133414332302211 is 112203233414331.
133414332302211 is digitally balanced in base 4, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 133414332302211 - 217 = 133414332171139 is a prime.
It is not an unprimeable number, because it can be changed into a prime (133414332302221) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 15516850 + ... + 22530008.
It is an arithmetic number, because the mean of its divisors is an integer number (5837193331200).
Almost surely, 2133414332302211 is an apocalyptic number.
133414332302211 is a deficient number, since it is larger than the sum of its proper divisors (53375854296189).
133414332302211 is a wasteful number, since it uses less digits than its factorization.
133414332302211 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7016719.
The product of its (nonzero) digits is 31104, while the sum is 33.
Adding to 133414332302211 its reverse (112203233414331), we get a palindrome (245617565716542).
The spelling of 133414332302211 in words is "one hundred thirty-three trillion, four hundred fourteen billion, three hundred thirty-two million, three hundred two thousand, two hundred eleven".
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