Base | Representation |
---|---|
bin | 11110010101011110010110… |
… | …011110010010011110011111 |
3 | 122111101112211122112201101012 |
4 | 132111132112132102132133 |
5 | 114441401201432404142 |
6 | 1151430544445405435 |
7 | 40050031645325162 |
oct | 3625362636223637 |
9 | 574345748481335 |
10 | 133417093638047 |
11 | 3956896520059a |
12 | 12b6916286987b |
13 | 595a240c4063b |
14 | 24d35c954dad9 |
15 | 1065741207882 |
hex | 79579679279f |
133417093638047 has 4 divisors (see below), whose sum is σ = 135024528501240. Its totient is φ = 131809658774856.
The previous prime is 133417093637987. The next prime is 133417093638071. The reversal of 133417093638047 is 740836390714331.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 133417093638047 - 226 = 133417026529183 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (133417093638077) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 803717431472 + ... + 803717431637.
It is an arithmetic number, because the mean of its divisors is an integer number (33756132125310).
Almost surely, 2133417093638047 is an apocalyptic number.
133417093638047 is a deficient number, since it is larger than the sum of its proper divisors (1607434863193).
133417093638047 is an equidigital number, since it uses as much as digits as its factorization.
133417093638047 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1607434863192.
The product of its (nonzero) digits is 27433728, while the sum is 59.
The spelling of 133417093638047 in words is "one hundred thirty-three trillion, four hundred seventeen billion, ninety-three million, six hundred thirty-eight thousand, forty-seven".
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