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13342013042 = 26671006521
BaseRepresentation
bin11000110110011111…
…01111011001110010
31021102211100111011012
430123033233121302
5204311023404132
610043525350522
7651425145131
oct143317573162
937384314135
1013342013042
115727244966
122704268442
1313481bc697
14907d57918
155314ae0b2
hex31b3ef672

13342013042 has 4 divisors (see below), whose sum is σ = 20013019566. Its totient is φ = 6671006520.

The previous prime is 13342013033. The next prime is 13342013057. The reversal of 13342013042 is 24031024331.

13342013042 is digitally balanced in base 5, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 24031024331 = 182691315399.

It can be written as a sum of positive squares in only one way, i.e., 12367886521 + 974126521 = 111211^2 + 31211^2 .

It is a junction number, because it is equal to n+sod(n) for n = 13342012999 and 13342013017.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3335503259 + ... + 3335503262.

Almost surely, 213342013042 is an apocalyptic number.

13342013042 is a deficient number, since it is larger than the sum of its proper divisors (6671006524).

13342013042 is an equidigital number, since it uses as much as digits as its factorization.

13342013042 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6671006523.

The product of its (nonzero) digits is 1728, while the sum is 23.

Adding to 13342013042 its reverse (24031024331), we get a palindrome (37373037373).

The spelling of 13342013042 in words is "thirteen billion, three hundred forty-two million, thirteen thousand, forty-two".

Divisors: 1 2 6671006521 13342013042