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13342110234199 = 23580091749313
BaseRepresentation
bin1100001000100111001110…
…1111011011011001010111
31202020111022121021002122021
43002021303233123121113
53222044120204443244
644213140354114011
72544635633535115
oct302116357333127
952214277232567
1013342110234199
1142843a244323a
1215b595987b907
1375a203acb766
14341a93ac6ab5
151820d3c17284
hexc2273bdb657

13342110234199 has 4 divisors (see below), whose sum is σ = 13922201983536. Its totient is φ = 12762018484864.

The previous prime is 13342110234169. The next prime is 13342110234251. The reversal of 13342110234199 is 99143201124331.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13342110234199 - 211 = 13342110232151 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13342110234119) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 290045874634 + ... + 290045874679.

It is an arithmetic number, because the mean of its divisors is an integer number (3480550495884).

Almost surely, 213342110234199 is an apocalyptic number.

13342110234199 is a deficient number, since it is larger than the sum of its proper divisors (580091749337).

13342110234199 is an equidigital number, since it uses as much as digits as its factorization.

13342110234199 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 580091749336.

The product of its (nonzero) digits is 139968, while the sum is 43.

The spelling of 13342110234199 in words is "thirteen trillion, three hundred forty-two billion, one hundred ten million, two hundred thirty-four thousand, one hundred ninety-nine".

Divisors: 1 23 580091749313 13342110234199