13342123110034 has 4 divisors (see below), whose sum is σ = 20013184665054. Its totient is φ = 6671061555016.

The previous prime is 13342123110031. The next prime is 13342123110049. The reversal of 13342123110034 is 43001132124331.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 13303869617809 + 38253492225 = 3647447^2 + 195585^2 .

It is a junction number, because it is equal to n+sod(n) for n = 13342123109984 and 13342123110011.

It is not an unprimeable number, because it can be changed into a prime (13342123110031) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3335530777507 + ... + 3335530777510.

Almost surely, 2^{13342123110034} is an apocalyptic number.

13342123110034 is a deficient number, since it is larger than the sum of its proper divisors (6671061555020).

13342123110034 is an equidigital number, since it uses as much as digits as its factorization.

13342123110034 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6671061555019.

The product of its (nonzero) digits is 5184, while the sum is 28.

Adding to 13342123110034 its reverse (43001132124331), we get a palindrome (56343255234365).

The spelling of 13342123110034 in words is "thirteen trillion, three hundred forty-two billion, one hundred twenty-three million, one hundred ten thousand, thirty-four".