Base | Representation |
---|---|
bin | 111110001000010000… |
… | …1101000111011010101 |
3 | 110202101100121020122012 |
4 | 1330100201220323111 |
5 | 4141221314140041 |
6 | 141143132114005 |
7 | 12432205554026 |
oct | 1742041507325 |
9 | 422340536565 |
10 | 133421240021 |
11 | 516468a2423 |
12 | 21a36605905 |
13 | c773926304 |
14 | 6659a04c4d |
15 | 370d3b43eb |
hex | 1f10868ed5 |
133421240021 has 4 divisors (see below), whose sum is σ = 134304824544. Its totient is φ = 132537655500.
The previous prime is 133421240009. The next prime is 133421240041. The reversal of 133421240021 is 120042124331.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-133421240021 is a prime.
It is a Duffinian number.
It is a Curzon number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (133421240041) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 441792035 + ... + 441792336.
It is an arithmetic number, because the mean of its divisors is an integer number (33576206136).
Almost surely, 2133421240021 is an apocalyptic number.
It is an amenable number.
133421240021 is a deficient number, since it is larger than the sum of its proper divisors (883584523).
133421240021 is an equidigital number, since it uses as much as digits as its factorization.
133421240021 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 883584522.
The product of its (nonzero) digits is 1152, while the sum is 23.
Adding to 133421240021 its reverse (120042124331), we get a palindrome (253463364352).
The spelling of 133421240021 in words is "one hundred thirty-three billion, four hundred twenty-one million, two hundred forty thousand, twenty-one".
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