Base | Representation |
---|---|
bin | 11000110110100011… |
… | …10000110011111111 |
3 | 1021102212100102021002 |
4 | 30123101300303333 |
5 | 204311142334403 |
6 | 10043545000515 |
7 | 651432513401 |
oct | 143321606377 |
9 | 37385312232 |
10 | 13342543103 |
11 | 572757712a |
12 | 270448313b |
13 | 1348346a26 |
14 | 908054b71 |
15 | 531566188 |
hex | 31b470cff |
13342543103 has 4 divisors (see below), whose sum is σ = 13345084488. Its totient is φ = 13340001720.
The previous prime is 13342543069. The next prime is 13342543169. The reversal of 13342543103 is 30134524331.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 30134524331 = 9689 ⋅3110179.
It is a cyclic number.
It is not a de Polignac number, because 13342543103 - 28 = 13342542847 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13342545103) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1262801 + ... + 1273322.
It is an arithmetic number, because the mean of its divisors is an integer number (3336271122).
Almost surely, 213342543103 is an apocalyptic number.
13342543103 is a deficient number, since it is larger than the sum of its proper divisors (2541385).
13342543103 is an equidigital number, since it uses as much as digits as its factorization.
13342543103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2541384.
The product of its (nonzero) digits is 12960, while the sum is 29.
The spelling of 13342543103 in words is "thirteen billion, three hundred forty-two million, five hundred forty-three thousand, one hundred three".
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