Base | Representation |
---|---|
bin | 1100001000101110110001… |
… | …1011010011000111010111 |
3 | 1202020200112201012212220001 |
4 | 3002023230123103013113 |
5 | 3222112242030004120 |
6 | 44214113323552131 |
7 | 2545040051010013 |
oct | 302135433230727 |
9 | 52220481185801 |
10 | 13344135000535 |
11 | 4285241366149 |
12 | 15b622398b647 |
13 | 75a467437851 |
14 | 341c0698b543 |
15 | 1821a186ce0a |
hex | c22ec6d31d7 |
13344135000535 has 16 divisors (see below), whose sum is σ = 16859583468000. Its totient is φ = 10111149288576.
The previous prime is 13344135000517. The next prime is 13344135000557. The reversal of 13344135000535 is 53500053144331.
It is a cyclic number.
It is not a de Polignac number, because 13344135000535 - 211 = 13344134998487 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13344135000494 and 13344135000503.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 15555060 + ... + 16390489.
It is an arithmetic number, because the mean of its divisors is an integer number (1053723966750).
Almost surely, 213344135000535 is an apocalyptic number.
13344135000535 is a deficient number, since it is larger than the sum of its proper divisors (3515448467465).
13344135000535 is a wasteful number, since it uses less digits than its factorization.
13344135000535 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 31949970.
The product of its (nonzero) digits is 162000, while the sum is 37.
Adding to 13344135000535 its reverse (53500053144331), we get a palindrome (66844188144866).
The spelling of 13344135000535 in words is "thirteen trillion, three hundred forty-four billion, one hundred thirty-five million, five hundred thirty-five", and thus it is an aban number.
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