Base | Representation |
---|---|
bin | 10011011010110001010… |
… | …001011101010110001101 |
3 | 11201120100121101002000211 |
4 | 103122301101131112031 |
5 | 133330334441140040 |
6 | 2501004335122421 |
7 | 165260010620350 |
oct | 23326121352615 |
9 | 4646317332024 |
10 | 1334414005645 |
11 | 474a15a10a76 |
12 | 196750673411 |
13 | 98ab0ab73a6 |
14 | 4882bd16297 |
15 | 24aa03028ea |
hex | 136b145d58d |
1334414005645 has 16 divisors (see below), whose sum is σ = 1831221439488. Its totient is φ = 914442773760.
The previous prime is 1334414005597. The next prime is 1334414005699. The reversal of 1334414005645 is 5465004144331.
It is not a de Polignac number, because 1334414005645 - 221 = 1334411908493 is a prime.
It is a super-3 number, since 3×13344140056453 (a number of 37 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1334414005598 and 1334414005607.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 12110476 + ... + 12220165.
It is an arithmetic number, because the mean of its divisors is an integer number (114451339968).
Almost surely, 21334414005645 is an apocalyptic number.
It is an amenable number.
1334414005645 is a deficient number, since it is larger than the sum of its proper divisors (496807433843).
1334414005645 is a wasteful number, since it uses less digits than its factorization.
1334414005645 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 24332220.
The product of its (nonzero) digits is 345600, while the sum is 40.
Adding to 1334414005645 its reverse (5465004144331), we get a palindrome (6799418149976).
The spelling of 1334414005645 in words is "one trillion, three hundred thirty-four billion, four hundred fourteen million, five thousand, six hundred forty-five".
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