Base | Representation |
---|---|
bin | 1100001000110100000001… |
… | …0011110000111010000011 |
3 | 1202020211011210022200200102 |
4 | 3002031000103300322003 |
5 | 3222123132312432210 |
6 | 44214505115313015 |
7 | 2545116656652416 |
oct | 302150023607203 |
9 | 52224153280612 |
10 | 13345542311555 |
11 | 42858a3798803 |
12 | 15b655714b76b |
13 | 75a62cb75c6c |
14 | 341cdb843b7d |
15 | 1822351a8ea5 |
hex | c23404f0e83 |
13345542311555 has 16 divisors (see below), whose sum is σ = 16033478616288. Its totient is φ = 10663882944000.
The previous prime is 13345542311537. The next prime is 13345542311617. The reversal of 13345542311555 is 55511324554331.
It is not a de Polignac number, because 13345542311555 - 234 = 13328362442371 is a prime.
It is a Duffinian number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 150478925 + ... + 150567585.
It is an arithmetic number, because the mean of its divisors is an integer number (1002092413518).
Almost surely, 213345542311555 is an apocalyptic number.
13345542311555 is a deficient number, since it is larger than the sum of its proper divisors (2687936304733).
13345542311555 is an equidigital number, since it uses as much as digits as its factorization.
13345542311555 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 123718.
The product of its digits is 2700000, while the sum is 47.
Adding to 13345542311555 its reverse (55511324554331), we get a palindrome (68856866865886).
The spelling of 13345542311555 in words is "thirteen trillion, three hundred forty-five billion, five hundred forty-two million, three hundred eleven thousand, five hundred fifty-five".
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