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13346125441042 = 26673062720521
BaseRepresentation
bin1100001000110110001100…
…0100001110100000010010
31202020212200102120201221211
43002031203010032200102
53222130331103103132
644215043030010334
72545140300325402
oct302154304164022
952225612521854
1013346125441042
1142860729735a9
1215b669a4a69aa
1375a6c39159b4
14341d55078802
1518226b493147
hexc236310e812

13346125441042 has 4 divisors (see below), whose sum is σ = 20019188161566. Its totient is φ = 6673062720520.

The previous prime is 13346125441013. The next prime is 13346125441043. The reversal of 13346125441042 is 24014452164331.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 10020130680681 + 3325994760361 = 3165459^2 + 1823731^2 .

It is a junction number, because it is equal to n+sod(n) for n = 13346125440986 and 13346125441004.

It is not an unprimeable number, because it can be changed into a prime (13346125441043) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3336531360259 + ... + 3336531360262.

Almost surely, 213346125441042 is an apocalyptic number.

13346125441042 is a deficient number, since it is larger than the sum of its proper divisors (6673062720524).

13346125441042 is an equidigital number, since it uses as much as digits as its factorization.

13346125441042 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6673062720523.

The product of its (nonzero) digits is 276480, while the sum is 40.

The spelling of 13346125441042 in words is "thirteen trillion, three hundred forty-six billion, one hundred twenty-five million, four hundred forty-one thousand, forty-two".

Divisors: 1 2 6673062720521 13346125441042