Base | Representation |
---|---|
bin | 1100001000110110001100… |
… | …0100001110100000010010 |
3 | 1202020212200102120201221211 |
4 | 3002031203010032200102 |
5 | 3222130331103103132 |
6 | 44215043030010334 |
7 | 2545140300325402 |
oct | 302154304164022 |
9 | 52225612521854 |
10 | 13346125441042 |
11 | 42860729735a9 |
12 | 15b669a4a69aa |
13 | 75a6c39159b4 |
14 | 341d55078802 |
15 | 18226b493147 |
hex | c236310e812 |
13346125441042 has 4 divisors (see below), whose sum is σ = 20019188161566. Its totient is φ = 6673062720520.
The previous prime is 13346125441013. The next prime is 13346125441043. The reversal of 13346125441042 is 24014452164331.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 10020130680681 + 3325994760361 = 3165459^2 + 1823731^2 .
It is a junction number, because it is equal to n+sod(n) for n = 13346125440986 and 13346125441004.
It is not an unprimeable number, because it can be changed into a prime (13346125441043) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3336531360259 + ... + 3336531360262.
Almost surely, 213346125441042 is an apocalyptic number.
13346125441042 is a deficient number, since it is larger than the sum of its proper divisors (6673062720524).
13346125441042 is an equidigital number, since it uses as much as digits as its factorization.
13346125441042 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6673062720523.
The product of its (nonzero) digits is 276480, while the sum is 40.
The spelling of 13346125441042 in words is "thirteen trillion, three hundred forty-six billion, one hundred twenty-five million, four hundred forty-one thousand, forty-two".
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