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133464543645331 = 472928222572139
BaseRepresentation
bin11110010110001010100010…
…101101101100111010010011
3122111120002022112002211121101
4132112022202231230322103
5114443140341133122311
61151504433120005231
740053331544614633
oct3626124255547223
9574502275084541
10133464543645331
1139586aa4524348
1212b763a5760817
1359618635c8c22
1424d5a0b3386c3
151066abbc98ec1
hex7962a2b6ce93

133464543645331 has 4 divisors (see below), whose sum is σ = 133492766222200. Its totient is φ = 133436321068464.

The previous prime is 133464543645313. The next prime is 133464543645379. The reversal of 133464543645331 is 133546345464331.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 133464543645331 - 217 = 133464543514259 is a prime.

It is a super-2 number, since 2×1334645436453312 (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (133464543646331) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14111281341 + ... + 14111290798.

It is an arithmetic number, because the mean of its divisors is an integer number (33373191555550).

Almost surely, 2133464543645331 is an apocalyptic number.

133464543645331 is a deficient number, since it is larger than the sum of its proper divisors (28222576869).

133464543645331 is an equidigital number, since it uses as much as digits as its factorization.

133464543645331 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 28222576868.

The product of its digits is 55987200, while the sum is 55.

The spelling of 133464543645331 in words is "one hundred thirty-three trillion, four hundred sixty-four billion, five hundred forty-three million, six hundred forty-five thousand, three hundred thirty-one".

Divisors: 1 4729 28222572139 133464543645331