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133464543645313 is a prime number
BaseRepresentation
bin11110010110001010100010…
…101101101100111010000001
3122111120002022112002211120201
4132112022202231230322001
5114443140341133122223
61151504433120005201
740053331544614606
oct3626124255547201
9574502275084521
10133464543645313
1139586aa4524331
1212b763a5760801
1359618635c8c0a
1424d5a0b3386ad
151066abbc98ead
hex7962a2b6ce81

133464543645313 has 2 divisors, whose sum is σ = 133464543645314. Its totient is φ = 133464543645312.

The previous prime is 133464543645271. The next prime is 133464543645379. The reversal of 133464543645313 is 313546345464331.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 116031179737729 + 17433363907584 = 10771777^2 + 4175328^2 .

It is a cyclic number.

It is not a de Polignac number, because 133464543645313 - 233 = 133455953710721 is a prime.

It is not a weakly prime, because it can be changed into another prime (133464543645413) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66732271822656 + 66732271822657.

It is an arithmetic number, because the mean of its divisors is an integer number (66732271822657).

Almost surely, 2133464543645313 is an apocalyptic number.

It is an amenable number.

133464543645313 is a deficient number, since it is larger than the sum of its proper divisors (1).

133464543645313 is an equidigital number, since it uses as much as digits as its factorization.

133464543645313 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 55987200, while the sum is 55.

The spelling of 133464543645313 in words is "one hundred thirty-three trillion, four hundred sixty-four billion, five hundred forty-three million, six hundred forty-five thousand, three hundred thirteen".