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13349368453 = 73182868061
BaseRepresentation
bin11000110111010111…
…10011001010000101
31021110100012011212211
430123223303022011
5204314414242303
610044351143421
7651544521361
oct143353631205
937410164784
1013349368453
115730409113
122706814b71
1313498965b5
14908d102a1
15531e6366d
hex31baf3285

13349368453 has 4 divisors (see below), whose sum is σ = 13532236588. Its totient is φ = 13166500320.

The previous prime is 13349368451. The next prime is 13349368489. The reversal of 13349368453 is 35486394331.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 6336478404 + 7012890049 = 79602^2 + 83743^2 .

It is a cyclic number.

It is not a de Polignac number, because 13349368453 - 21 = 13349368451 is a prime.

It is a super-2 number, since 2×133493684532 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13349368397 and 13349368406.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13349368451) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 91433958 + ... + 91434103.

It is an arithmetic number, because the mean of its divisors is an integer number (3383059147).

Almost surely, 213349368453 is an apocalyptic number.

It is an amenable number.

13349368453 is a deficient number, since it is larger than the sum of its proper divisors (182868135).

13349368453 is an equidigital number, since it uses as much as digits as its factorization.

13349368453 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 182868134.

The product of its digits is 2799360, while the sum is 49.

The spelling of 13349368453 in words is "thirteen billion, three hundred forty-nine million, three hundred sixty-eight thousand, four hundred fifty-three".

Divisors: 1 73 182868061 13349368453