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13350102153 = 38941497711
BaseRepresentation
bin11000110111011101…
…00110010010001001
31021110101120110022220
430123232212102021
5204320111232103
610044415004253
7651553665423
oct143356462211
937411513286
1013350102153
11573086a383
122706b09689
131349a9253b
14909061813
1553205ac53
hex31bba6489

13350102153 has 8 divisors (see below), whose sum is σ = 17802162816. Its totient is φ = 8899054800.

The previous prime is 13350102151. The next prime is 13350102197. The reversal of 13350102153 is 35120105331.

13350102153 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 13350102153 - 21 = 13350102151 is a prime.

It is not an unprimeable number, because it can be changed into a prime (13350102151) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 222033 + ... + 275678.

It is an arithmetic number, because the mean of its divisors is an integer number (2225270352).

Almost surely, 213350102153 is an apocalyptic number.

It is an amenable number.

13350102153 is a deficient number, since it is larger than the sum of its proper divisors (4452060663).

13350102153 is an equidigital number, since it uses as much as digits as its factorization.

13350102153 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 506655.

The product of its (nonzero) digits is 1350, while the sum is 24.

Adding to 13350102153 its reverse (35120105331), we get a palindrome (48470207484).

The spelling of 13350102153 in words is "thirteen billion, three hundred fifty million, one hundred two thousand, one hundred fifty-three".

Divisors: 1 3 8941 26823 497711 1493133 4450034051 13350102153