1335013025401 has 4 divisors (see below), whose sum is σ = 1456377845904. Its totient is φ = 1213648204900.

The previous prime is 1335013025321. The next prime is 1335013025443. The reversal of 1335013025401 is 1045203105331.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1335013025401 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1335013025401.

It is not an unprimeable number, because it can be changed into a prime (1335013065401) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 60682410235 + ... + 60682410256.

It is an arithmetic number, because the mean of its divisors is an integer number (364094461476).

Almost surely, 2^{1335013025401} is an apocalyptic number.

1335013025401 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

1335013025401 is a deficient number, since it is larger than the sum of its proper divisors (121364820503).

1335013025401 is a wasteful number, since it uses less digits than its factorization.

1335013025401 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 121364820502.

The product of its (nonzero) digits is 5400, while the sum is 28.

The spelling of 1335013025401 in words is "one trillion, three hundred thirty-five billion, thirteen million, twenty-five thousand, four hundred one".