Base | Representation |
---|---|
bin | 111110001010101100… |
… | …1111010011011100101 |
3 | 110202121001122012022011 |
4 | 1330111121322123211 |
5 | 4141403243210040 |
6 | 141155214434221 |
7 | 12434221426525 |
oct | 1742531723345 |
9 | 422531565264 |
10 | 133503100645 |
11 | 51689024532 |
12 | 21a59b02971 |
13 | c787888555 |
14 | 6666833685 |
15 | 37156843ea |
hex | 1f1567a6e5 |
133503100645 has 4 divisors (see below), whose sum is σ = 160203720780. Its totient is φ = 106802480512.
The previous prime is 133503100637. The next prime is 133503100663. The reversal of 133503100645 is 546001305331.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 92465254561 + 41037846084 = 304081^2 + 202578^2 .
It is a cyclic number.
It is not a de Polignac number, because 133503100645 - 23 = 133503100637 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13350310060 + ... + 13350310069.
It is an arithmetic number, because the mean of its divisors is an integer number (40050930195).
Almost surely, 2133503100645 is an apocalyptic number.
It is an amenable number.
133503100645 is a deficient number, since it is larger than the sum of its proper divisors (26700620135).
133503100645 is an equidigital number, since it uses as much as digits as its factorization.
133503100645 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 26700620134.
The product of its (nonzero) digits is 16200, while the sum is 31.
Adding to 133503100645 its reverse (546001305331), we get a palindrome (679504405976).
The spelling of 133503100645 in words is "one hundred thirty-three billion, five hundred three million, one hundred thousand, six hundred forty-five".
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