13350522403045 has 4 divisors (see below), whose sum is σ = 16020626883660. Its totient is φ = 10680417922432.

The previous prime is 13350522403037. The next prime is 13350522403067. The reversal of 13350522403045 is 54030422505331.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 7520659033924 + 5829863369121 = 2742382^2 + 2414511^2 .

It is a cyclic number.

It is not a de Polignac number, because 13350522403045 - 2³ = 13350522403037 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13350522402995 and 13350522403013.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1335052240300 + ... + 1335052240309.

It is an arithmetic number, because the mean of its divisors is an integer number (4005156720915).

Almost surely, 2^{13350522403045} is an apocalyptic number.

It is an amenable number.

13350522403045 is a deficient number, since it is larger than the sum of its proper divisors (2670104480615).

13350522403045 is an equidigital number, since it uses as much as digits as its factorization.

13350522403045 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2670104480614.

The product of its (nonzero) digits is 216000, while the sum is 37.

Adding to 13350522403045 its reverse (54030422505331), we get a palindrome (67380944908376).

The spelling of 13350522403045 in words is "thirteen trillion, three hundred fifty billion, five hundred twenty-two million, four hundred three thousand, forty-five".