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13351455345545 = 52670291069109
BaseRepresentation
bin1100001001001010000011…
…0000001100101110001001
31202021101102212201221102022
43002102200300030232021
53222222240032024140
644221323544214225
72545416336632522
oct302224060145611
952241385657368
1013351455345545
11428835851a759
1215b772746a375
1375b062c12a45
143422dcc95849
1518247e3640b5
hexc24a0c0cb89

13351455345545 has 4 divisors (see below), whose sum is σ = 16021746414660. Its totient is φ = 10681164276432.

The previous prime is 13351455345469. The next prime is 13351455345581. The reversal of 13351455345545 is 54554355415331.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 3804028953664 + 9547426391881 = 1950392^2 + 3089891^2 .

It is a cyclic number.

It is not a de Polignac number, because 13351455345545 - 242 = 8953408834441 is a prime.

It is a super-2 number, since 2×133514553455452 (a number of 27 digits) contains 22 as substring.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1335145534550 + ... + 1335145534559.

It is an arithmetic number, because the mean of its divisors is an integer number (4005436603665).

Almost surely, 213351455345545 is an apocalyptic number.

It is an amenable number.

13351455345545 is a deficient number, since it is larger than the sum of its proper divisors (2670291069115).

13351455345545 is an equidigital number, since it uses as much as digits as its factorization.

13351455345545 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2670291069114.

The product of its digits is 27000000, while the sum is 53.

The spelling of 13351455345545 in words is "thirteen trillion, three hundred fifty-one billion, four hundred fifty-five million, three hundred forty-five thousand, five hundred forty-five".

Divisors: 1 5 2670291069109 13351455345545