Base | Representation |
---|---|
bin | 11000110111101011… |
… | …10001000110001011 |
3 | 1021110112002221020112 |
4 | 30123311301012023 |
5 | 204321101401301 |
6 | 10044523144535 |
7 | 651605653424 |
oct | 143365610613 |
9 | 37415087215 |
10 | 13351981451 |
11 | 5731933316 |
12 | 270767514b |
13 | 134a29ca53 |
14 | 9093d064b |
15 | 5322cc9bb |
hex | 31bd7118b |
13351981451 has 4 divisors (see below), whose sum is σ = 13391601912. Its totient is φ = 13312360992.
The previous prime is 13351981439. The next prime is 13351981457. The reversal of 13351981451 is 15418915331.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13351981451 - 218 = 13351719307 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 13351981399 and 13351981408.
It is not an unprimeable number, because it can be changed into a prime (13351981457) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 19809725 + ... + 19810398.
It is an arithmetic number, because the mean of its divisors is an integer number (3347900478).
Almost surely, 213351981451 is an apocalyptic number.
13351981451 is a deficient number, since it is larger than the sum of its proper divisors (39620461).
13351981451 is an equidigital number, since it uses as much as digits as its factorization.
13351981451 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 39620460.
The product of its digits is 64800, while the sum is 41.
The spelling of 13351981451 in words is "thirteen billion, three hundred fifty-one million, nine hundred eighty-one thousand, four hundred fifty-one".
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