Base | Representation |
---|---|
bin | 11000110111101011… |
… | …10001000110010001 |
3 | 1021110112002221020202 |
4 | 30123311301012101 |
5 | 204321101401312 |
6 | 10044523144545 |
7 | 651605653433 |
oct | 143365610621 |
9 | 37415087222 |
10 | 13351981457 |
11 | 5731933321 |
12 | 2707675155 |
13 | 134a29ca59 |
14 | 9093d0653 |
15 | 5322cc9c2 |
hex | 31bd71191 |
13351981457 has 2 divisors, whose sum is σ = 13351981458. Its totient is φ = 13351981456.
The previous prime is 13351981439. The next prime is 13351981469. The reversal of 13351981457 is 75418915331.
13351981457 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 12047038081 + 1304943376 = 109759^2 + 36124^2 .
It is a cyclic number.
It is not a de Polignac number, because 13351981457 - 226 = 13284872593 is a prime.
It is not a weakly prime, because it can be changed into another prime (13351981757) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6675990728 + 6675990729.
It is an arithmetic number, because the mean of its divisors is an integer number (6675990729).
Almost surely, 213351981457 is an apocalyptic number.
It is an amenable number.
13351981457 is a deficient number, since it is larger than the sum of its proper divisors (1).
13351981457 is an equidigital number, since it uses as much as digits as its factorization.
13351981457 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 453600, while the sum is 47.
The spelling of 13351981457 in words is "thirteen billion, three hundred fifty-one million, nine hundred eighty-one thousand, four hundred fifty-seven".
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