13352000933 has 4 divisors (see below), whose sum is σ = 13354180608. Its totient is φ = 13349821260.

The previous prime is 13352000903. The next prime is 13352000947. The reversal of 13352000933 is 33900025331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13352000933 - 2¹⁰ = 13351999909 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13352000896 and 13352000905.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13352000903) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1080623 + ... + 1092908.

It is an arithmetic number, because the mean of its divisors is an integer number (3338545152).

Almost surely, 2^13352000933 is an apocalyptic number.

It is an amenable number.

13352000933 is a deficient number, since it is larger than the sum of its proper divisors (2179675).

13352000933 is an equidigital number, since it uses as much as digits as its factorization.

13352000933 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2179674.

The product of its (nonzero) digits is 7290, while the sum is 29.

The spelling of 13352000933 in words is "thirteen billion, three hundred fifty-two million, nine hundred thirty-three", and thus it is an aban number.