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13352012220314 = 26676006110157
BaseRepresentation
bin1100001001001100000111…
…1100100000011110011010
31202021102212200121002222202
43002103001330200132122
53222224410112022224
644221455120050202
72545436211166235
oct302230174403632
952242780532882
1013352012220314
1142886138a2a39
1215b7861a63962
1375b1213bc441
14342352c1441c
151824b31b3eae
hexc24c1f2079a

13352012220314 has 4 divisors (see below), whose sum is σ = 20028018330474. Its totient is φ = 6676006110156.

The previous prime is 13352012220311. The next prime is 13352012220329. The reversal of 13352012220314 is 41302221025331.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 9754484429089 + 3597527791225 = 3123217^2 + 1896715^2 .

It is not an unprimeable number, because it can be changed into a prime (13352012220311) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3338003055077 + ... + 3338003055080.

Almost surely, 213352012220314 is an apocalyptic number.

13352012220314 is a deficient number, since it is larger than the sum of its proper divisors (6676006110160).

13352012220314 is an equidigital number, since it uses as much as digits as its factorization.

13352012220314 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6676006110159.

The product of its (nonzero) digits is 8640, while the sum is 29.

Adding to 13352012220314 its reverse (41302221025331), we get a palindrome (54654233245645).

The spelling of 13352012220314 in words is "thirteen trillion, three hundred fifty-two billion, twelve million, two hundred twenty thousand, three hundred fourteen".

Divisors: 1 2 6676006110157 13352012220314