Base | Representation |
---|---|
bin | 1100001001001100000111… |
… | …1100100000100000100011 |
3 | 1202021102212200121010011211 |
4 | 3002103001330200200203 |
5 | 3222224410112023301 |
6 | 44221455120050551 |
7 | 2545436211166522 |
oct | 302230174404043 |
9 | 52242780533154 |
10 | 13352012220451 |
11 | 42886138a3053 |
12 | 15b7861a63a57 |
13 | 75b1213bc518 |
14 | 342352c144b9 |
15 | 1824b31b4051 |
hex | c24c1f20823 |
13352012220451 has 8 divisors (see below), whose sum is σ = 13374533975040. Its totient is φ = 13329502702152.
The previous prime is 13352012220433. The next prime is 13352012220467. The reversal of 13352012220451 is 15402221025331.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 13352012220451 - 29 = 13352012219939 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13352015220451) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 873555 + ... + 5240908.
It is an arithmetic number, because the mean of its divisors is an integer number (1671816746880).
Almost surely, 213352012220451 is an apocalyptic number.
13352012220451 is a deficient number, since it is larger than the sum of its proper divisors (22521754589).
13352012220451 is an equidigital number, since it uses as much as digits as its factorization.
13352012220451 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6118145.
The product of its (nonzero) digits is 14400, while the sum is 31.
Adding to 13352012220451 its reverse (15402221025331), we get a palindrome (28754233245782).
The spelling of 13352012220451 in words is "thirteen trillion, three hundred fifty-two billion, twelve million, two hundred twenty thousand, four hundred fifty-one".
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