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13352522524121 = 111213865684011
BaseRepresentation
bin1100001001001110000001…
…0111001010010111011001
31202021111012020211020012202
43002103200113022113121
53222231431231232441
644222021505415545
72545454645536364
oct302234027122731
952244166736182
1013352522524121
114288855957820
1215b798493a5b5
1375b1a3041461
143423a08cd0db
151824e2db519b
hexc24e05ca5d9

13352522524121 has 4 divisors (see below), whose sum is σ = 14566388208144. Its totient is φ = 12138656840100.

The previous prime is 13352522524111. The next prime is 13352522524127. The reversal of 13352522524121 is 12142522525331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13352522524121 - 26 = 13352522524057 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13352522524127) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 606932841995 + ... + 606932842016.

It is an arithmetic number, because the mean of its divisors is an integer number (3641597052036).

Almost surely, 213352522524121 is an apocalyptic number.

13352522524121 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

13352522524121 is a deficient number, since it is larger than the sum of its proper divisors (1213865684023).

13352522524121 is a wasteful number, since it uses less digits than its factorization.

13352522524121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1213865684022.

The product of its digits is 144000, while the sum is 38.

The spelling of 13352522524121 in words is "thirteen trillion, three hundred fifty-two billion, five hundred twenty-two million, five hundred twenty-four thousand, one hundred twenty-one".

Divisors: 1 11 1213865684011 13352522524121